QUESTION
SOLUTION
1.a) Given, the angular velocity of the arm OA=
i) Velocity of piston=
ii) Angular velocity=31.4 rad/sec
iii) Angular acceleration of point B= =
b) i) When the link AB makes 90 degree with the horizontal the velocity of b is maximum.
ii)
c) the maximum angular velocity is 600 rad/sec.
2(a).Since the system is in static equilibrium the centrifugal force would balance out the reaction forces, as:
Where, f is the centrifugal force on the mass.
,
Hence, m=8000/4929=1.62 Kg
Now, because of rotational equilibrium in the plane of the reaction forces:
(b)Here, we have two masses instead of one and the radius, . So,
3.24 kg.
3.a) The moment of inertia of the flywheel
So, torque on the flywheel= 7.36 Nm
Now, output power=* =7.36*31.42=231.30w
Given,
Also,
Now,
b)The magnitude of the holding torque=251.08 Nm in opposite direction as shown in the figure.
c) The input power has linear relationship with time.
References:
1. Physics by Resnick and Halliday .
2. College Physics
3.Schaum’s-700 problems in vector mechanics for engineers
KH08
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