Question1.
a)
y=5.6mm
d=1mm
x= 10000mm
tanƟ=y/x
sinƟ= sin(tan-1 (y/x))
wavelength= = 1/5.6=0.178mm
(b)
Lc = CxT =(300000*4.0E-13) = 1200000*10-13= 1.2*10-7 meter
(c)
N=18.5
n=1.517
.
Or,
Or, t=
t=3592
d=N *λ/2
d=18.5*589.2/2=5450
hence the difference (d-t)=1857
Hence the thickness of the glass is 1857
Question2.
(a)
.
Or,n==1.00029
(b)
d=N *λ/2
d=(2t/ λ)/( λ/2)
d=t
the diameter of the source is 30cm
(c)
The graph is the exact representation of CosƟ function
Hence the relation of coherence with the phase angle Ɵ is:
G∝CosƟ
The highest amplitude is I and the lowest is I/2 hence the effective amplitude of the wave is
. =
Hence the relation of coherence with the phase angle Ɵ is:
G∝(I/4)CosƟ
The axis of wave is at position of
Hence considering the 3I/4 displacement of oscillation axis from the x axis the equation is
Hence the degree of coherence is:
G=