EPIDEMOLOGY

QUESTION

Complete the answers (show your working for all calculations, not just the answer) and forward them to the Education Office by the nominated due date.

We do not expect, or want you to write a mini essay for each response. Succinct answers which cover all the relevant points are desirable. However, make sure you show the formulae and all workings for any calculations undertaken. This may allow us to still allocate you marks even if your final answer was incorrect (in the unlikely event this would occur!).

Question 1

You are given the following figures regarding acute cerebro vascular accident (brain stroke) events in females in the city ‘A’ for 2001:

  Age group
Gender 35-44 45-54 55-64 65-74 75-84 85-94 Total
Female 10 32 90 96 108 36 372
               

 

Total female population in the city ‘A’ for 2001:

  Age group
Gender 35-44 45-54 55-64 65-74 75-84 85-94 Total
Female 63,882 66,750 55,436 37,492 30,648 10,886 265,094
               

For comparison, you are given the age-specific brain stroke incidence rates for the national female population (per 100,000):

  Age group
Gender 35-44 45-54 55-64 65-74 75-84 85-94  
Female 9.3 38.9 147.9 229.3 319.7 257.2  
               

You are interested in knowing whether the rate in females seen in the city ‘A’ is higher or lower than the national average.

a)         What sort of standardisation would you use? (1 mark)

b)         Carry out this standardisation, showing intermediate steps. (5 marks)

c)         What conclusion do you come to?  Is the brain stroke incidence for females in  city ‘A’  higher or lower then the national incidence? (2 marks)

Question 2

 

Seven hundred men aged 45 years were given a health check and 56 were found to have ‘type 2 diabetes’. Eight years later all 7,00 men (assuming none of them died during this period of time) attended a second check and another 112 men had developed ‘type 2 diabetes’.

i)                 What was the prevalence of ‘type 2 diabetes’ in the men a) at the age 45 and b) at age 53? (1+ 1 = 2 marks)

ii)               How many men were ‘at risk’ of developing ‘type 2 diabetes’ at the start of the 8-year period? ( 1 mark)

iii)             What was the incidence of ‘type 2 diabetes’ in these men? Is this a measure of cumulative incidence or incidence density? (1+ 1 = 2 marks)

Let’s assume that on average, each of the 112 men who developed ‘type 2 diabetes’ did so half-way through the 8 year follow-up period.

iv)              Calculate the total number of person-years at risk (of developing ‘type 2 diabetes’) during the 8 years. (1 marks)

v)               What was the incidence rate of ‘type 2 diabetes’ in these men? (1 marks)

SOLUTION

Table 1

Age-Group            Brain Stroke(event)(2001)

City A

         Total population(2001)

City A

(Column2/column3)

*100000

Stroke rate in national population
1 2 3 4 5
35-44 10 63882 15.65 9.3
45-54 32 66750 47.94 38.9
55-64 90 55436 162.35 147.9
65-74 96 37492 256.05 229.3
75-84 108 30648 352.39 319.7
85-94 36 10886 330.7 257.2
total 372 265094 1165.08 1002.3
         

 

Question 1

a>

Here I use indirect standardization.

b>

e=∑ ei= total number of events in the study population (the observed number of events)=372

ei= number of events in the i th age group of the study population=column 2 of table 1

e(s)=∑ ei(s)=  total number of events in the standard population

ei(s)= number of events in the ith age group of the standard population

i(s)= ei(s)/pi(s)= event rate in the ith age group for the standard population=column 5/100000

e(s) /p(s)= be the overall event rate in the standard population=1002.3/100000

Pi(s)=total population of i th age group of standard population

E=expected number of events in the study population=

∑Ωi(s)*Pi=5.94+25.96+81.98+85.97+97.98+28=325.83

SER=standardized event ratio=(observed number of events/expected number of events)=e/E

=372/325.83=1.142

Standard error(SER)=√e/E=0.059

 

Indirect standardization rate(isr)=100000*SER* Ω(s)=100000*1.142*0.010023=1144.62

Standard error(isr)=100000* Ω(s)*standard error(SER)=100000*0.010023*0.059=59.13

 

c>

here indirect standardization rate is 1144.62 and standard error(isr)=59.13

and the observed stroke rate is calculated at column 4 of the table 1 is 1165.08. which is close to the indirect standardization rate. We cannot conclude at 5% level of significance that there be a valid diference between city A and national incidence.

 

Question 2.

 

(i)               a.

Prevalence is the number of existing cases of disease at a particular point of time.

So from this context I tell that 56 was the prevalence of ‘type 2 diabetes’ at the age 45.

 

b. 56+112=168 was the prevalence of ‘type 2 diabetes’ at the age 53.

 

 

 

(ii)             There are (700-168)=532 men were ‘at risk’ of developing ‘type 2 diabetes’ at the start of the 8-year period.

(iii)           Incidence is the number of new cases of disease within a specified period of time.

From this we conclude that another 112 men had developed ‘type 2 diabetes’ of the 8 year period is called the incident.

This is a measure of cumulative incidence.

 

 

(iv)            Total number of person- years at risk during the 8 years be

644+620+606+592+578+564+550+536=4690

 

(v)             14/644,14/620,14/606,14/592,14/578,14/564,14/550,14/536 was the incidence rate of ‘type 2 diabetes ’in these men.

JC33

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